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函数y=(x-cosx)/(x+sinx)在点x=2处的导数?
人气:170 ℃ 时间:2019-08-17 10:25:06
解答
y=(x-cosx)/(x+sinx)
y=[(1+sinx)*(x+sinx)-(x-cosx)*(1+cosx)]/(x+sinx)^2
=[sinx+cosx+x(sinx-cosx)+1]/(x+sinx)^2
f(2)=[sin2+cos2+2sin2-2cos2+1]/(2+sin2)^2
=(3sin2-cos2+1)/(2+sin2)^2
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