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2log5(底)25-3log2(底)64求解
log2(底)(log2(底)32-log2(底)3/4+log2(底)6
人气:379 ℃ 时间:2020-04-17 16:55:30
解答
2log5(底)25-3log2(底)64=2*2-3*6=4-18=-14
log2(底)(log2(底)32-log2(底)3/4+log2(底)6
=log2(底)5-log2(底)3+log2(底)4+log2(底)6
=log2(底)5+3
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