依题意得因为,f(x)=8+2x-x^2,g(x)=f（2-x^2）所以,g(x)=f（2-x^2)=8+2（2-x^2)-(2-x^2)^2=8+4-2x^2-4+4x^2-x^4=-x^4+2x^2+8则,g'(x)=-4x^3+4x=-4x(x^2+1)令g'(x)>0,即-4x(x^2+1)>0,g(x)单调递增解得x...