(√3+√3i)³·(3-4i)/4+3i
=3√3(1+i)³·(3-4i)/4+3i
=3√3·2i(1+i)(3-4i)/4+3i
=3√3·2i(7-i)/4+3i
=(21√3i+3√3)/2+3i
=[6i+21(√3)i+3√3]/2