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数学
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x趋向0(cosx+sinx)的x分之一次 求极限
人气:217 ℃ 时间:2020-02-06 12:33:03
解答
等价替换
ln(x+1)~x 1-cosx~x^2/2是x的高阶无穷小 sinx~x
原式=lime^{[ln(cosx+sinx)]/x}
=lime^{[cosx+sinx-1]/x}
=e
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