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数学
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-﹙x2+y2﹚+[﹣3xy-﹙x2+y2﹚]
人气:459 ℃ 时间:2020-05-04 08:49:50
解答
原式=-x2-y2﹣3xy-﹙x2+y2﹚
=-x2-y2﹣3xy-x2-y2
=-2x2-2y2﹣3xy-﹙x的2次方+y的2次方﹚+[﹣3xy-﹙x的2次方+y的2次方﹚]对采纳吧
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