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【数学】一道关于函数的证明题
已知:f(x)=ax+b
求证:f[(x1+x2)/2]=f{[(x1)+f(x2)]/2]}
人气:472 ℃ 时间:2020-05-14 14:34:55
解答
F(X)=AX+B
f(x1)+f(x2)
=ax1+b+ax2+b
=a(x1+x2)+2b
1/2[f(x1)+f(x2)]
=a/2(x1+x2)+b
f((x1+x2)/2)
=a(x1+x2)/2+b
=a/2(x1+x2)+b
所以f(x1+x2/2)=[f(x1)+f(x2)]/2
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