数列{an}中,a1=0,a2=2,a(n+2)-6a(n+1)+5an=2^n,求an
(n+2),(n+1)均为下标
人气：221 ℃ 时间：2020-05-09 06:21:35
解答
1、设b[n]=a[n]+⅓×2^n,那么b[1] = a[1] + ⅓×2 = ⅔b[2] = a[2] + ⅓×2^2 = 10/3且有 a[n] = b[n] - ⅓×2^n,代入 a[n+2] - 6a[n+1] + 5a[n] = 2^n 并整理,有b[n+2] - 6b[n+1] + 5b[n]...
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