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计算:a-1/a²-1+a/a+1;1/m²-m+m-3/m²-1.
人气:460 ℃ 时间:2020-02-05 14:08:08
解答
a-1/a²-1+a/a+1;
=(a-1)/(a+1)(a-1) + a/(a+1)
= 1/(a+1) + a/(a+1)
= (1+a)/(a+1)
=1
1/m²-m+m-3/m²-1.
=1/m(m-1) +(m-3)/(m+1)(m-1)
=(m+1+m^2 -3m)/m(m+1)(m-1)
=(m^2-2m+1)/m(m+1)(m-1)
=(m-1)^2/m(m+1)(m-1)
=(m-1)/m(m+1)
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