先分解部分分式：设1/(x+1)(x^2+1)=a/(x+1)+(bx+c)/(x^2+1)去分母：1=a(x^2+1)+(bx+c)(x+1)1=(a+b)x^2+(b+c)x+a+c对比系数得:a+b=0,b+c=0,a+c=1解得：a=c=0.5,b=-0.5所以1/(x+1)=0.5/(x+1)+(-0.5x+0.5)/(x^2+1)=0.5/...