a(n)=81*q^(n-1),
b(n)=log_{3}[a(n)] = log_{3} [81*q^(n-1)] = log_{3}(81) + log_{3}[q^(n-1)]
=4 + (n-1)log_{3}(q)
{b(n)}为首项为4,公差为log_{3}(q)的等差数列.