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证明不等式2ab/(a+b)<=√ab<=
人气:199 ℃ 时间:2020-05-16 08:20:07
解答
a+b>=2√ab
(a+b)/2>=√ab
1/(a+b)<=1/(2√ab)
2ab/(a+b)<=2ab/(2√ab)<=√ab<=(a+b)/2
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