求串联电路消耗的电功率.
标有“6V 3W” 灯泡L1和标有“6V 2W”的灯泡L2串联在电流为0.1A的电路,此时它们消耗的电功率各是多少?
人气:270 ℃ 时间:2020-04-27 06:08:47
解答
R1=U1²/P1=(6V)²/3w=12Ω
R2=U2²/P2=(6V)²/2w=18Ω
P1'=I'²R1=(0.1A)²*12Ω=0.12w
P2'=I'²R2=(0.1A)²*18Ω=0.18w
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