设这四个连整数为n,n+1,n+2,n+3,n*(n+1）*(n+2）*(n+3)+1=n^4+6n^3+11n^2+6n+1=（n^4+6n^3+9n^2)+（2n^2+6n)+1=[n(n+3)]^2+2n（n+3）+1=[n(n+3)+1]^2即证明了四个连整数n,n+1,n+2,n+3的积与1的和是一个完全平方数：[...