> 数学 >
化简 (21 21:8:15)
sin(2a+b)/sina-2cos(a+b)
人气:216 ℃ 时间:2020-02-03 04:26:44
解答
sin(2a+b)/sina-2cos(a+b)=[sin(2a+b)-2cos(a+b)sina]/sina =[sina*cos(a+b)+sin(a+b)*cosa-2cos(a+b)sina]/sina =[sin(a+b)*cosa-cos(a+b)sina]/sina =sin(a+b-a)/sina=sinb/sina
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版