sin[α-(π/3)]+cos[α+(13π/6)]=sin(α-π/3)+cos(α+π/6)=sinαcosπ/3-cosαsinπ/3+cosαcosπ/6-sinαsinπ/6=(1/2)sinα-(√3/2)cosα+(√3/2)cosα-(1/2)sinα=0sin[α-(5π/4)]+cos[α+(π/2)]=sinαcos5...