| du |
| dx |
| ∂f |
| ∂x |
| ∂f |
| ∂y |
| dy |
| dx |
| ∂f |
| ∂z |
| dz |
| dx |
由exy-xy=2，两边对x求导得：
exy(y+x
| dy |
| dx |
| dy |
| dx |
解得：
| dy |
| dx |
| y |
| x |
又由ex=
| ∫ | x-z0 |
| sint |
| t |
ex=
| sin(x-z) |
| x-z |
| dz |
| dx |
解得：
| dz |
| dx |
| (x-z)ex |
| sin(x-z) |
将
| dy |
| dx |
| dz |
| dx |
| du |
| dx |
| ∂f |
| ∂x |
| y |
| x |
| ∂f |
| ∂y |
| ex(x-z) |
| sin(x-z) |
| ∂f |
| ∂z |
| ∫ | x-z0 |
| sint |
| t |
| du |
| dx |
| du |
| dx |
| ∂f |
| ∂x |
| ∂f |
| ∂y |
| dy |
| dx |
| ∂f |
| ∂z |
| dz |
| dx |
| dy |
| dx |
| dy |
| dx |
| dy |
| dx |
| y |
| x |
| ∫ | x-z0 |
| sint |
| t |
| sin(x-z) |
| x-z |
| dz |
| dx |
| dz |
| dx |
| (x-z)ex |
| sin(x-z) |
| dy |
| dx |
| dz |
| dx |
| du |
| dx |
| ∂f |
| ∂x |
| y |
| x |
| ∂f |
| ∂y |
| ex(x-z) |
| sin(x-z) |
| ∂f |
| ∂z |