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若x=√2+1=√2-1 求x²-y²分之x²-3xy=y²的值
人气:401 ℃ 时间:2020-05-24 16:10:34
解答
x=√2+1,y=√2-1
x²-y²
=(√2+1)^2-(√2-1)^2
=4√2
x²-3xy+y²
(x-y)^2-xy
=4-1
=3
(x²-y²)/(x²-3xy+y²)
=4√2/3
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