(1）(2/3√9x)+(2√x/4)-(3x√1/x)
=(2/3)*3√x+(2/2)*√x-(3x/x)*√x
=2√x+vx-3√x
=0
(2)6√0.75+√18-√12-3√1/3-0/√2
=6√(3/4)+√9*2-√4*3-3√3/9-0
=(6/2)*√3+3√2-2√3-(3/3)√3
=3√3+3√2-2v3-√3
=3√2