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计算[log9(5)+log3(5)]乘[log25(3)+log125(9)]
人气:423 ℃ 时间:2020-03-28 04:17:56
解答
换底公式
=(lg5/lg9+lg5/lg3)(lg3/lg25+lg9/lg125)
=(lg5/2lg3+lg5/lg3)(lg3/2lg5+2lg3/3lg5)
=(1/2+1)*lg5/lg3*(1/2+2/3)*(lg3/lg5
约分
=(3/2)(7/6)
=7/4
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