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数学
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∫[(x^2-x+6)/(x^3+3x)]dx
人气:324 ℃ 时间:2020-02-03 18:24:16
解答
(x^2-x+6)/(x^3+3x)=2/x-(x+1)/(x^2+3).
原式=∫2/xdx-∫(x+1)/(x^2+3)dx
=2ln|x|-(1/2)ln(x^2+3)-(1/√3)arctan(x/√3)+C.
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