解决方法：①题意,C =√^ 2-B ^ 2 = 1,∴F2（1,0）的k =tanπ/ 4 = 1
∴直线方程为y-0 = 1（x-1的）,它是为y = x-1的
为y = x-1的生成到椭圆x 2/4 + Y 2/3 = 1以简化的精加工7倍^ 2-8倍速8 = 0
| AB | =√1 +1 ^ 2 *√（8/7）^ 2-4 * -8 / 7 = 24/7
（ 2）易问F1的直线距离D = | -1-1 | /√1 ^ 2 +（-1）^ 2 =√2
∴S△AF1B = 1 / 2 * 24/7 *√2 = 12√2/7
③7倍^ 2-8倍速-8 = 0有X1 + X2 = 8/7横坐标弦AB的中点（1次+×2）/ 2 = 4/7
Y1 =的x1-1 Y2 = x2的-1 Y1 + Y2 =×1 +×2-2 = 10 -6 / 7
所以弦AB的中点的垂直坐标（Y1 + Y2）/ 2 = -3 / 7
AB中点的坐标为（4/7,-3 / 7）