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lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
写出过程.
人气:466 ℃ 时间:2020-06-17 10:05:44
解答
首先a=0,否则极限不存在.
又lim (n→∞)[(an^2+bn+c)/(2n+5)]
=lim (n→∞)[(bn+c)/(2n+5)]
=lim (n→∞)[(b+c/n)/(2+5/n)]
=b/2=3
∴b=6.
∴a=0,b=6.
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