已知tana=1,3sinB=sin(2a+B),求tan(a+B)的值.(要具体过程)
人气:364 ℃ 时间:2020-02-03 19:02:48
解答
3sin(A+B-A)=sin(A+B+A) 3sin(A+B)cosA-3cos(A+B)sinA=sin(A+B)cosA+cos(A+B)sinA 2sin(A+B)cosA-4cos(A+B)sinA=0 sin(A+B)cosA-2cos(A+B)sinA=0 两边都除以cos(A+B)cosA tan(A+B)-2tanA=0 tan(A+B)=2tanA因为tanA=1...
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