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求定积分∫(dx)/(x+(1-x^2)^1/2),积分上限是1,积分下限是0,
人气:238 ℃ 时间:2019-09-21 06:42:36
解答
令x=sint ,dx=costdtt (0到pi/2) pi表示圆周率P=∫(dx)/(x+(1-x^2)^1/2)dx=∫(0到pi/2) costdt/(sint+cost)令t=pi/2-mP=∫(pi/2到0)sinmd(-m)/(cosm+sinm)=∫(0到pi/2) sintdt/(cost+sint)两式相加所以2P==∫(0...
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