函数y=3x-2与函数y=-4x+3的函数图象交于点A,且两图象分别与y轴交与点B和c.求B、C两点的坐标,求△ABC面积
必须有求B、C点的步骤
人气:206 ℃ 时间:2019-08-20 06:27:54
解答
令3x-2=-4x+3得
x=5/7
所以y=3*5/7-2=1/7
所以A(5/7,1/7)
令x=0得y=3*0-2=-2
所以B(0,-2)
令x=0得y=-4*0+3=3
所以C(0,3)
故|BC|=5
所以△ABC面积是S=(1/2)*5*(5/7)=25/14
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