> 数学 >
求不定积分∫x^2/(x^4-x^2+1)dx
人气:429 ℃ 时间:2020-03-25 23:26:26
解答
∫x^2dx/(x^4-x^2+1)=(1/2)∫xdx^2/[(x^2+1)^2-3x^2]=(1/4√3)∫(2√3x)dx^2/[(x^2+1+√3x)(x^2+1-√3x)]=(1/4√3)[∫dx^2/(x^2+1-√3x)-∫dx^2/(x^2+1+√3x)]=(1/4√3) [∫d(x^2-√3x+1)/(x^2+1-√3x) +∫√3dx/(x^...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版