令x=2+3+4+……+98+99则原式=(x+1)/(x+100)=(2x+2)/(2x+200)=(100x+100)/(100x+10000)1/2=(x+100)/(2x+200),99/100=(99x+9900)/(100x+10000)只需比较①x+100与2x+2、②99x+9900与100x+100的大小即可①作差：(2x+2)-(...