怎么这么多这种题,都是一样的解法,直接就是代换法啊!
x^(1/3)=y,x=y^3
原式变为∫e^ydy^3=∫3y^2de^y=3y^2*e^y-∫e^yd3y^2=3y^2*e^y-∫e^y*6ydy=3y^2*e^y-6∫yde^y=3y^2*e^y-6ye^y-e^y
代会得到3(x)^(2/3)*e^(x^(1/3))-6(x^(1/3))*e^(x^(1/3))-e^(x^(1/3))