(2+2i)/(√3-i) = (2+2i)(√3+i)/ (3+1) =0.5(1+i)(√3+i)(2-2i)/(1+√3i) = (2-2i)(1-√3i)/(1+3) = 0.5(1-i)(1-√3i)=-0.5(1+i)(√3+i)因此,原式=[0.5(1+i)(√3+i)]^7-[-0.5(1+i)(√3+i) ]^7= 2*[0.5*(1+i)(√3+i)...