设函数f(x)=e^x,x≧0,x²,x
人气：205 ℃ 时间：2020-03-29 18:15:33
解答
=∫（-1,1）f(x)dx = ∫(-1,0)f(x)dx + ∫（0,1)f(x)dx = e - 2/3
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