设函数f(x)=e^x,x≧0,x²,x
人气:205 ℃ 时间:2020-03-29 18:15:33
解答
=∫(-1,1)f(x)dx = ∫(-1,0)f(x)dx + ∫(0,1)f(x)dx = e - 2/3
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