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f(x)=sin(ωx+φ)(ω大于0,φ大于等于0 小于等于π)为偶函数,其图像上相邻的两个最高点之间的距离为2π
已知函数f(x)=sin(ωx+φ)(ω大于0,0≤φ≤π)为偶函数,其图像上相邻的两个最高点之间的距离为2π
1.求f(x)的解析式
2.若a属于(-π/3,π/2),f(a+(π/3))=1/3,求sin(2a+(5π/3))的值
人气:259 ℃ 时间:2019-08-18 10:04:07
解答
T=2π,w=1,因为偶函数,φ=π/2,所以sin(x+π/2)f(a+(π/3))=sin(a+π/3+π/2)sin(a+5π/6)==cos(π/2-a-5π/6)=cos(-a-π/3)=1/3cos(a+π/3)=1/3 所以sin(a+π/3)=根号8除以9a属于(-π/3,π/2),sin(2a+(...
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