y=log2(a^2x+2a^x-2)不对题。思路差不多y=log2(a^2x+2a^x)>0即y=log2(a^2x+2a^x-2)>log2(1)所以a^2x+2a^x>1令m=a^x,则a^2x=m²,且m>0m²+2m>1解得m>√2-1所以a^x>√2-1 若01,则loga(x)是增函数所以x>loga(√2-1) 综上：01，x>loga(√2-1)