y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy
人气:179 ℃ 时间:2019-11-09 04:06:55
解答
y=f[(x-1)/(x+1)],f'(x)=arctanx^2,求dy/dx,dy两边对x求导:dy/dx=f'[(x-1)/(x+1)]*2/(x+1)^2=arctan[(x-1)/(x+1)]^2*2/(x+1)^2dy=f'[(x-1)/(x+1)]*2/(x+1)^2=arctan[(x-1)/(x+1)]^2*2/(x+1)^2*dx
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