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sina=5/13,a属于(π/2,π),求sin(a+π/4),cos(a-π/6),tan(a+π/3)
人气:422 ℃ 时间:2020-03-22 12:18:06
解答
sin(a+π/4)=sinacosπ/4-cosasinπ/4=17√2/26
cos(a-π/6)=cosacosπ/6-sinasinπ/6
tan(a+π/3)=(tana+tanπ/3)/(1-tanatanπ/3)
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