> 数学 >
(1)
−3
2x−4
÷
1
x−2
x2−4
x2+3x−2

(2)
1−x2
x2−x−6
• 
9−6x+x2
2x2+6x+4
÷
x2−4x+3
5x2+20x+20
人气:379 ℃ 时间:2019-12-20 19:34:25
解答
(1)原式=
−3
2(x−2)
×
x−2
1
×
(x+2)(x−2)
x2+3x−2

=-
3x2−12
2x2+6x−4

(2)原式=
−(x+1)(x−1)
(x−3)(x+2)
×
(x−3)2
2(x+1)(x+2)
×
5(x+2)2
(x−3)(x−1)

=-
5
2
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