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y=xsin2x+cosx的微分
人气:416 ℃ 时间:2020-06-18 08:04:51
解答
dy=d(xsin2x)+dcosx
=sin2xdx+xdsin2x-sinxdx
=sin2xdx+xcos2xd2x-sinxdx
=sin2xdx+2xcos2xdx-sinxdx
=(sin2x+2xcos2x-sinx)dx
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