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化简sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π)
答案是cota,我做出来是-cota 求解!
人气:112 ℃ 时间:2020-03-28 10:29:14
解答
sin(a-π)cot(a-2π)/cos(a-π)tan(a-2π)
=-[sin(π-a)cota]/[cos(π-a)tana]
=-[sina*cota]/-[cosatana]
=cosa/sina
=cota
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