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已知x^2-5x-1997=0,求代数式[(x-2)(x-2)-(x-1)(x-1)+1]/(x-2)的值...
人气:141 ℃ 时间:2019-08-20 17:45:11
解答
[(x-2)(x-2)-(x-1)(x-1)+1]/(x-2)
={[(x-2)+(x-1)][(x-2)-(x-1)]+1}/(x-2)
=[-(2x-3)+1]/(x-2)
=(4-2x)/(x-2)
=-2
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