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已知sin(π-α)cos(-α+3π/2)/cos(-π-α),且α为第三象限角1.化简f(α)2.若cos(α+π/2)=1/5,求f(α)的值
人气:481 ℃ 时间:2020-01-28 21:02:49
解答
f(α) = sin(π-α)cos(-α+3π/2)/cos(-π-α)= sinα cos(-α+2π-π/2)/cos(π+α)= sinα cos(α+π/2)/(-cosα)= sinα (-sinα)/(-cosα)= sin^2α/cosαα为第三象限角cos(α+π/2)=1/5-sinα = 1/5sinα =...
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