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F(x)=(sinx一cosx)sin2x/sinx 单调减区间
人气:481 ℃ 时间:2020-03-28 04:17:39
解答
F(x)=(sinx一cosx)sin2x/sinx=2(sinx一cosx)cosx=sin2x-cos2x-1=√2sin(2x-π/4)
所以F(x)单调减区间为:π/2+2kπ
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