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数学题如果(tana+1)/(1-tana)=2008,求1/cos2a+tan2a
人气:184 ℃ 时间:2020-07-02 14:23:51
解答
2008
cos2A=(1-tanA^2)/(1+tanA^2)
tan2A=2tanA/(1+tanA^2)
1/cos2a+tan2a=(1+2tanA+tanA^2)/(1-tanA^2)
=(1+tanA)/(1-tanA)=2008
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