你错了,答案是1/e²lim(x->0) (1-2x)^(1/sinx)=lim [1+(-2x)]^[1/(-2x)]*(-2x/sinx),前面的配合公式lim(x->0) (1+x)^(1/x) = e=e^lim (-2x/sinx)=e^-2*lim x/sinx=e^-2*[1/lim (sinx/x)]=e^-2*(1/1)=1/e²...