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sin405°-cos(-4分之9π)=?
人气:267 ℃ 时间:2020-10-01 21:45:30
解答
sin405°-cos(-4分之9π)
=sin(360°+45°)-cos(-9π/4+2π)
=sin45°-cos(-π/4)
=sin45°-cosπ/4
=sin45°-cos45°
=sin45°-cos(90°-45°)
=sin45°-sin45°
=0
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