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几道数学题,得到正解给100
(1-1/6+3/44)*(-48)
-2+1/2/(-2)
(-7/30)/(3/5-1/6-2/3)
(8-1又1/3-0.4)/(-4/3)
(-24)/(-2又2/3)+(-4又1/5)*10
(-1又2/3)*(-7/2)/(-5/4)
第一题打错了 应该是(1-1/6+3/4)*(-48)
人气:144 ℃ 时间:2020-09-21 07:25:12
解答
(1-1/6+3/4)*(-48)
=-48+8-36
=-76
-2+1/2/(-2)
=-2-1
=-3
(-7/30)/(3/5-1/6-2/3)
=(-7/30)/[(18-5-20)/30]
=(-7/30)/(33/30)
=-7/30×30/33
=-7/33
(8-1又1/3-0.4)/(-4/3)
=(8-1-1/3-2/5)×(-4/3)
=(7-11/15)×(-4/3)
=66/15×(-4/3)
=-264/45
(-24)/(-2又2/3)+(-4又1/5)*10
=24/(8/3)-21/5×10
=24×3/8-21/5×10
=9-42
=-33
(-1又2/3)*(-7/2)/(-5/4)
=-5/3×7/2×4/5
=-14/3不对吧,,,,同号得正啊最后一题:三个负数的积为负前面几题都应该为正啊同号相乘得正,同号相加取相同的符号(正加正为正,负加负为负)前两个都应该是负号,,因为他们是省略加号的和啊哪个题?前两个(1-1/6+3/4)*(-48)
=-48+8-36 乘法分配率
=-76

纠正第2题
(-7/30)/(3/5-1/6-2/3)
=(-7/30)/[(18-5-20)/30]分母统分
=(-7/30)/(-17/30) 分母合并
=-7/30×30/(-17)
=7/17
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