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z=u^2v,u=xcosy,v=xsiny 求αz/αx和αz/αy
人气:213 ℃ 时间:2020-10-02 03:00:49
解答
u=xcosy,∴du=cosydx-xsinydy,v=xsiny ,∴dv=sinydx+xcosydy,z=u^2*v,∴dz=2uvdu+u^2*dv=2x^2*sinycosy(cosydx-xsinydy)+x^2*(cosy)^2*(sinydx+xcosydy)=3x^2*siny(cosy)^2*dx+x^3*[(cosy)^2-2(siny)^2]cosydy,∴z'x...
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