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数学
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[x(x^2y^2-xy)-y(x^2-x^3y)]/(2x^2y)
人气:315 ℃ 时间:2019-12-06 10:29:40
解答
您好: [x(x^2y^2-xy)-y(x^2-x^3y)]/(2x^2y)=(x^3y^2-x^2y-x^2y+x^3y^2)/(2x^2y)=(2x^3y^2-2x^2y)/(2x^2y)=xy-1 如果本题有什么不明白可以追问,如果满意记得采纳如果有其他问题请采纳本题后另发点击向我求助,答题...
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