CaCO3+2HCl=CaCl2+H2O+CO2
100 44
x 66g
100/x=44/66g
x=150g
该石灰石中碳酸钙的质量分数 150g/200g*100%=75%
C+O2=点燃=CO2
12 44
y 66g
12/y=44/66g
y=18g