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1.(3x^2y-xy^2+2/1xy)除以(-2/1xy) 2.(16x^3-8x^2+4x)除以(-2x) 3.[6(2x-y)^2-x(2x-y)]除以(2x-y)
计算题
人气:131 ℃ 时间:2020-01-29 12:05:06
解答
1.(3x^2y-xy^2+2/1xy)除以(-2/1xy)
=3x^2y除以(-2/1xy) -xy^2除以(-2/1xy) +2/1xy除以(-2/1xy)
=-6x+2y-1
2.(16x^3-8x^2+4x)除以(-2x)
=16x^3除以(-2x) -8x^2除以(-2x) +4x除以(-2x)
=-8x^2+4x-2
3.[6(2x-y)^2-x(2x-y)]除以(2x-y)
=6(2x-y)^2除以(2x-y)-x(2x-y)除以(2x-y)
=6(2x-y)-x
=13x-6y
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