两式想减
x^2-y^2+√2y-√2√x=0
(x+y)(x-y)-√2(x-y)=0
x不等于y则x-y不等于0
把x-y约分
x+y-√2=0
x+y=√2
两式相加
(x^2+y^2)+√2(x+y)=2√3
(x+y)^2-2xy+√2(x+y)=2√3
x+y=√2
所以2-2xy+2=2√3
xy=2-√3
y/x+x/y
=(x^2+y^2)/xy
=[(x+y)^2-2xy]/xy
=(2-4+2√3)/(2-√3)
=2√3+2